codominio x/(x^2-6x+8)

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

θ

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∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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vertici y=6x7 · 4x3

Solution

Minimo (0, 0)

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Solve by:

Trova il vertice utilizzando la forma polinomiale

Trova il vertice utilizzando la forma della parabola

Trova il vertice usando la forma del vertice

Trovare il vertice usando la media delle radici

One step at a time

y=6x7 · 4x3

Parabola equazione nel polinomio forma

Il vertice di una parabola rivolta verso l'alto e verso il basso della forma y=ax²+bx+c è x_v=−b2a

Riscrivi y=6x7 · 4x3 nella forma y=ax²+bx+c

y=8x²7

I parametri della parabola sono:

a=87 , b=0, c=0

x_v=−b2a

x_v=−02(87 )

Semplificare

x_v=0

Inserire x_v=0 per trovare il y_v valore

y_v=0

Quindi il vertice della parabola è

(0, 0)

Se a<0, allora il vertice è un massimo valore
Se a>0, allora il vertice è un minimo valore
a=87

Minimo (0, 0)

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CIAO, Fai una domanda su vertici y=6x7 · 4x3 oppure scegli tra le opzioni qui sotto

Risolvi per: Trova il vertice utilizzando la forma della parabola

Risolvi per: Trova il vertice usando la forma del vertice

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

codominio x/(x^2-6x+8)

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