prove that 4(x-3)^2-21=4x^2-24x+15

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

θ

∞

∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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next term a_n=3n+2

Solution

a₁=5

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a_n=3n+2

Trova il tipo di successione per a_n=3n+2: Serie aritmetica: d=3, a_n=3n+2

No term was given, finding first term

Trova il primo termine della successionea_n=3n+2: a₁=5

a₁=5

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sequenza tipo a_n=3n+2

primo termine a_n=3n+2

nth termine a_n=3n+2

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

prove that 4(x-3)^2-21=4x^2-24x+15

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