nth term a_{n}=3n+2

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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codominio y=xx²+4

Solution

−14 ≤ f(x)≤14

Interval Notation

[−14 , 14 ]

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Solution steps

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Definizione dell'intervallo di valori della funzione

L'insieme dei valori della variabile dipendente per i quali è definita una funzione

Riscrivi come

xx²+4 =y

Moltiplica entrambi i lati per x²+4

x=y(x²+4)

L'intervallo è l'insieme di y per il quale il discriminante è maggiore o uguale a zero

Discriminante x=y(x²+4): 1−16y²

1−16y²≥ 0 : −14 ≤ y≤ 14

Controlla se gli estremi dell'intervallo di intervallo sono inclusi

y=−14 : Incluso

y=14 : Incluso

Quindi l'intervallo è

−14 ≤ f(x)≤ 14

Solve instead

dominio xx²+4

inversa xx²+4

intercettano xx²+4

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

nth term a_{n}=3n+2

Solution

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