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(2x-4)/3 = 1/9+1/8 x

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(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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vertici y=x²+2x+3

Solution

Minimo (−1, 2)

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Trova il vertice utilizzando la forma polinomiale

Trova il vertice utilizzando la forma della parabola

Trova il vertice usando la forma del vertice

One step at a time

y=x²+2x+3

Parabola equazione nel polinomio forma

Il vertice di una parabola rivolta verso l'alto e verso il basso della forma y=ax²+bx+c è x_v=−b2a

I parametri della parabola sono:

a=1, b=2, c=3

x_v=−b2a

x_v=−22· 1

Semplificare

x_v=−1

Inserire x_v=−1 per trovare il y_v valore

y_v=2

Quindi il vertice della parabola è

(−1, 2)

Se a<0, allora il vertice è un massimo valore
Se a>0, allora il vertice è un minimo valore
a=1

Minimo (−1, 2)

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

(2x-4)/3 = 1/9+1/8 x

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