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slope of and intercepts f(x)=sqrt(x+3)

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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raggio (x−4)²+(y+2)²=25

Solution

r=5

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(x−4)²+(y+2)²=25

Equazione del cerchio

(x−a)²+(y−b)²=r² è l'equazione del cerchio con raggio r, centrato in (a, b)

Riscrivere (x−4)²+(y+2)²=25 nella forma dell'equazione della circonferenza standard

(x−4)²+(y−(−2))²=5²

Pertanto, le proprietà del cerchio sono:

(a, b)=(4, −2), r=5

E il raggio è:

r=5

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

slope of and intercepts f(x)=sqrt(x+3)

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