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trasformata di laplace inversa 1x32
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Solution
2√t√π
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Solve by:
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L−1{1x32}
=L−1{2√π·(2·1−1)!!√π21x1+12}
Usa la proprietà della moltiplicazione costante dell' inversa trasformata di Laplace: Per la funzione f(t) e la costante a:L−1{a·f(t)}=a·L−1{f(t)}
=2√πL−1{(2·1−1)!!√π21x1+12}
Usa la tabella delle trasformate di Laplace: L−1{(2n−1)!!√π2nsn+12}=tn−12