asintoti (x-3)(x+1)

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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trasformata di laplace inversa 5x+27x 2x

Solution

114 (5H(t)+2t)

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L⁻¹{5x+27x 2x }

Usa la proprietà della moltiplicazione costante dell' inversa trasformata di Laplace:
Per la funzione f(t) e la costante a: L⁻¹{a·f(t)}=a·L⁻¹{f(t)}

=17 2 L⁻¹{5x+2x x }

L⁻¹{5x+2x x }: 5H(t)+2t

=17 2 (5H(t)+2t)

Raffinare 17 2 · (5H(t)+2t): 114 (5H(t)+2t)

=114 (5H(t)+2t)

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

asintoti (x-3)(x+1)

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