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5^{-30} \mod7

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
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dimostrare tan²(x)−sin²(x)=tan²(x)sin²(x)

Solution

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Solution steps

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tan²(x)−sin²(x)=tan²(x)sin²(x)

Manipolando il lato destro

tan²(x)sin²(x)

Riscrivere utilizzando identità trigonometriche

=tan²(x)(1−cos²(x))

Espandi (1−cos²(x))tan²(x): tan²(x)−tan²(x)cos²(x)

=tan²(x)−cos²(x)tan²(x)

Riscrivere utilizzando identità trigonometriche

=tan²(x)−sin²(x)

Abbiamo mostrato che i due lati possono prendere la stessa forma

⇒ Vero

Negative Power Mod Examples

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

5^{-30} \mod7

Solution

Solution steps

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