derivative of (x-2(x^2+2x+4))

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

θ

∞

∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

simplify solve for expand factor rationalize

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codominio 1x−3

Solution

f(x)<0 or f(x)>0

Interval Notation

(−∞ , 0)∪(0, ∞ )

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Definizione dell'intervallo di valori della funzione

L'insieme dei valori della variabile dipendente per i quali è definita una funzione

L'intervallo di funzione è il dominio combinato delle funzioni inverse

Trovare la funzione o le funzioni inverse di: 1x−3

Inversa di 1x−3 : 1x +3

1x +3

Trovare il dominio di ogni funzione inversa

Dominio di 1x +3 : x<0 or x>0

Combina gli intervalli

f(x)<0 or f(x)>0

Solve instead

dominio 1x−3

inversa 1x−3

intercettano 1x−3

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

derivative of (x-2(x^2+2x+4))

Solution

Solution steps

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