inversa (x^2+x+1)/x

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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lim_{x→ ∞}(x²−6x+8x−4 )

Solution

∞

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lim_{x→ ∞}(x²−6x+8x−4 )

Semplifica x²−6x+8x−4 : x−2

=lim_{x→ ∞}(x−2)

Applicare la proprietà dell'infinito: lim_x→∞(axⁿ+⋯+bx+c)=∞, a>0, n è dispari
a=1, n=1

=∞

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

inversa (x^2+x+1)/x

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