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absolute extreme points of y= x/(x^2-6x+8)

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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global extreme points y=xx²−6x+8

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Global extreme points definition

f(x) has a global maximum at x₀ on the interval (a, b) if f(x₀) ≥ f(x) for all x in (a, b)
f(x) has a global minimum at x₀ on the interval (a, b) if f(x₀) ≤ f(x) for all x in (a, b)

Find the extreme points: Minimum(−2√2, −3−2√22 ), Maximum(2√2, −2√2+32 )

Find the function range: (−∞ , −√2−32 ]∪ [√2−32 , ∞ )

Verify extreme points are global points

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domain xx²−6x+8

range xx²−6x+8

inverse xx²−6x+8

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

absolute extreme points of y= x/(x^2-6x+8)

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