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inversa 3/x

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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vertici x²−2x−24

Solution

Minimo (1, −25)

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Trova il vertice utilizzando la forma polinomiale

Trova il vertice utilizzando la forma della parabola

Trova il vertice usando la forma del vertice

Trovare il vertice usando la media delle radici

One step at a time

y=x²−2x−24

Parabola equazione nel polinomio forma

Il vertice di una parabola rivolta verso l'alto e verso il basso della forma y=ax²+bx+c è x_v=−b2a

I parametri della parabola sono:

a=1, b=−2, c=−24

x_v=−b2a

x_v=−(−2)2· 1

Semplificare

x_v=1

Inserire x_v=1 per trovare il y_v valore

y_v=−25

Quindi il vertice della parabola è

(1, −25)

Se a<0, allora il vertice è un massimo valore
Se a>0, allora il vertice è un minimo valore
a=1

Minimo (1, −25)

Order of operations multi-step without parentheses Examples

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CIAO, Fai una domanda su vertici x²−2x−24 oppure scegli tra le opzioni qui sotto

Risolvi per: Trova il vertice utilizzando la forma della parabola

Risolvi per: Trova il vertice usando la forma del vertice

Risolvi per: Trovare il vertice usando la media delle radici

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

inversa 3/x

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