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codominio (x^2+x+1)/x

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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log_□

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ddx

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autovalori (

1	2
3	4

)

Solution

λ=5+√332 , λ=5−√332

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Solution steps

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(

1	2
3	4

)

Autovalori della matrice

Sia A una matrice quadrata, η un vettore e λ uno scalare tale che Aη=λη,
allora λ è chiamato l'autovalore associato al corrispondente autovettore η di A

Gli autovalori di A sono le radici dell' equazione caratteristica det(A−λ I)=0

det((

1	2
3	4

)−λ(

1	0
0	1

)): λ²−5λ−2

Risolvi λ²−5λ−2=0: λ=5+√332 , λ=5−√332

Gli autovalori sono:

λ=5+√332 , λ=5−√332

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1	2
3	4

) oppure scegli qui sotto

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

codominio (x^2+x+1)/x

Solution

Solution steps

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