We've updated our
Privacy Policy effective December 15. Please read our updated Privacy Policy and tap

Study Guides > College Algebra

Rational Expressions

A pastry shop has fixed costs of $280\$280 per week and variable costs of $9\$9 per box of pastries. The shop’s costs per week in terms of xx, the number of boxes made, is 280+9x280+9x. We can divide the costs per week by the number of boxes made to determine the cost per box of pastries.

280+9xx\frac{280+9x}{x}

Notice that the result is a polynomial expression divided by a second polynomial expression. In this section, we will explore quotients of polynomial expressions.

Multiply and Divide Rational Expressions

The quotient of two polynomial expressions is called a rational expression. We can apply the properties of fractions to rational expressions, such as simplifying the expressions by canceling common factors from the numerator and the denominator. To do this, we first need to factor both the numerator and denominator. Let’s start with the rational expression shown.
x2+8x+16x2+11x+28\frac{{x}^{2}+8x+16}{{x}^{2}+11x+28}
We can factor the numerator and denominator to rewrite the expression.
(x+4)2(x+4)(x+7)\frac{{\left(x+4\right)}^{2}}{\left(x+4\right)\left(x+7\right)}
Then we can simplify that expression by canceling the common factor (x+4)\left(x+4\right).
x+4x+7\frac{x+4}{x+7}

How To: Given a rational expression, simplify it.

  1. Factor the numerator and denominator.
  2. Cancel any common factors.

Example: Simplifying Rational Expressions

Simplify x2−9x2+4x+3\frac{{x}^{2}-9}{{x}^{2}+4x+3}.

Answer: \begin{array}\frac{\left(x+3\right)\left(x - 3\right)}{\left(x+3\right)\left(x+1\right)}\hfill & \hfill & \hfill & \hfill & \text{Factor the numerator and the denominator}.\hfill \\ \frac{x - 3}{x+1}\hfill & \hfill & \hfill & \hfill & \text{Cancel common factor }\left(x+3\right).\hfill \end{array}

Analysis of the Solution

We can cancel the common factor because any expression divided by itself is equal to 1.

Q & A

Can the x2{x}^{2} term be cancelled in the above example?

No. A factor is an expression that is multiplied by another expression. The x2{x}^{2} term is not a factor of the numerator or the denominator.

Try It

Simplify x−6x2−36\frac{x - 6}{{x}^{2}-36}.

Answer: 1x+6\frac{1}{x+6}

Multiplying Rational Expressions

Multiplication of rational expressions works the same way as multiplication of any other fractions. We multiply the numerators to find the numerator of the product, and then multiply the denominators to find the denominator of the product. Before multiplying, it is helpful to factor the numerators and denominators just as we did when simplifying rational expressions. We are often able to simplify the product of rational expressions.

How To: Given two rational expressions, multiply them.

  1. Factor the numerator and denominator.
  2. Multiply the numerators.
  3. Multiply the denominators.
  4. Simplify.

Example: Multiplying Rational Expressions

Multiply the rational expressions and show the product in simplest form:
(x+5)(x−1)3(x+6)⋅(2x−1)(x+5)Factor the numerator and denominator.(x+5)(x−1)(2x−1)3(x+6)(x+5)Multiply numerators and denominators.(x+5)(x−1)(2x−1)3(x+6)(x+5)Cancel common factors to simplify.(x−1)(2x−1)3(x+6)\begin{array}{cc}\frac{\left(x+5\right)\left(x - 1\right)}{3\left(x+6\right)}\cdot \frac{\left(2x - 1\right)}{\left(x+5\right)}\hfill & \text{Factor the numerator and denominator}.\hfill \\ \frac{\left(x+5\right)\left(x - 1\right)\left(2x - 1\right)}{3\left(x+6\right)\left(x+5\right)}\hfill & \text{Multiply numerators and denominators}.\hfill \\ \frac{\cancel{\left(x+5\right)}\left(x - 1\right)\left(2x - 1\right)}{3\left(x+6\right)\cancel{\left(x+5\right)}}\hfill & \text{Cancel common factors to simplify}.\hfill \\ \frac{\left(x - 1\right)\left(2x - 1\right)}{3\left(x+6\right)}\hfill & \hfill \end{array}

Answer:

(x+5)(x−1)3(x+6)⋅(2x−1)(x+5)Factor the numerator and denominator.(x+5)(x−1)(2x−1)3(x+6)(x+5)Multiply numerators and denominators.(x+5)(x−1)(2x−1)3(x+6)(x+5)Cancel common factors to simplify.(x−1)(2x−1)3(x+6)\begin{array}{cc}\frac{\left(x+5\right)\left(x - 1\right)}{3\left(x+6\right)}\cdot \frac{\left(2x - 1\right)}{\left(x+5\right)}\hfill & \text{Factor the numerator and denominator}.\hfill \\ \frac{\left(x+5\right)\left(x - 1\right)\left(2x - 1\right)}{3\left(x+6\right)\left(x+5\right)}\hfill & \text{Multiply numerators and denominators}.\hfill \\ \frac{\cancel{\left(x+5\right)}\left(x - 1\right)\left(2x - 1\right)}{3\left(x+6\right)\cancel{\left(x+5\right)}}\hfill & \text{Cancel common factors to simplify}.\hfill \\ \frac{\left(x - 1\right)\left(2x - 1\right)}{3\left(x+6\right)}\hfill & \hfill \end{array}

Try It

Multiply the rational expressions and show the product in simplest form:
x2+11x+30x2+5x+6⋅x2+7x+12x2+8x+16\frac{{x}^{2}+11x+30}{{x}^{2}+5x+6}\cdot \frac{{x}^{2}+7x+12}{{x}^{2}+8x+16}

Answer:  (x+5)(x+6)(x+2)(x+4)\frac{\left(x+5\right)\left(x+6\right)}{\left(x+2\right)\left(x+4\right)}

Dividing Rational Expressions

Division of rational expressions works the same way as division of other fractions. To divide a rational expression by another rational expression, multiply the first expression by the reciprocal of the second. Using this approach, we would rewrite 1x÷x23\frac{1}{x}\div \frac{{x}^{2}}{3} as the product 1x⋅3x2\frac{1}{x}\cdot \frac{3}{{x}^{2}}. Once the division expression has been rewritten as a multiplication expression, we can multiply as we did before.
1x⋅3x2=3x3\frac{1}{x}\cdot \frac{3}{{x}^{2}}=\frac{3}{{x}^{3}}

How To: Given two rational expressions, divide them.

  1. Rewrite as the first rational expression multiplied by the reciprocal of the second.
  2. Factor the numerators and denominators.
  3. Multiply the numerators.
  4. Multiply the denominators.
  5. Simplify.

Example: Dividing Rational Expressions

Divide the rational expressions and express the quotient in simplest form:
2x2+x−6x2−1÷x2−4x2+2x+1\frac{2{x}^{2}+x - 6}{{x}^{2}-1}\div \frac{{x}^{2}-4}{{x}^{2}+2x+1}

Answer:

\begin{array}\text{ }\frac{2x^{2}+x-6}{x^{2}}\cdot\frac{x^{2}+2x+1}{x^{2}-4} \hfill& \text{Rewrite as the first rational expression multiplied by the reciprocal of the second rational expression.} \\ \frac{\left(2\times3\right)\cancel{\left(x+2\right)}}{\cancel{\left(x+1\right)}\left(x-1\right)}\cdot\frac{\cancel{\left(x+1\right)}\left(x+1\right)}{\cancel{\left(x+2\right)}\left(x-2\right)} \hfill& \text{Factor and cancel common factors.} \\ \frac{\left(2x+3\right)\left(x+1\right)}{\left(x-1\right)\left(x-2\right)} \hfill& \text{Multiply numerators and denominators.} \\ \frac{2x^{2}+5x+3}{x^{2}-3x+2} \hfill& \text{Simplify.}\end{array}

Try It

Divide the rational expressions and express the quotient in simplest form:
9x2−163x2+17x−28÷3x2−2x−8x2+5x−14\frac{9{x}^{2}-16}{3{x}^{2}+17x - 28}\div \frac{3{x}^{2}-2x - 8}{{x}^{2}+5x - 14}

Answer: 11

Add and Subtract Rational Expressions

Adding and subtracting rational expressions works just like adding and subtracting numerical fractions. To add fractions, we need to find a common denominator. Let’s look at an example of fraction addition.
524+140=25120+3120=28120=730\begin{array}{ccc}\hfill \frac{5}{24}+\frac{1}{40}& =& \frac{25}{120}+\frac{3}{120}\hfill \\ & =& \frac{28}{120}\hfill \\ & =& \frac{7}{30}\hfill \end{array}
We have to rewrite the fractions so they share a common denominator before we are able to add. We must do the same thing when adding or subtracting rational expressions. The easiest common denominator to use will be the least common denominator, or LCD. The LCD is the smallest multiple that the denominators have in common. To find the LCD of two rational expressions, we factor the expressions and multiply all of the distinct factors. For instance, if the factored denominators were (x+3)(x+4)\left(x+3\right)\left(x+4\right) and (x+4)(x+5)\left(x+4\right)\left(x+5\right), then the LCD would be (x+3)(x+4)(x+5)\left(x+3\right)\left(x+4\right)\left(x+5\right). Once we find the LCD, we need to multiply each expression by the form of 1 that will change the denominator to the LCD. We would need to multiply the expression with a denominator of (x+3)(x+4)\left(x+3\right)\left(x+4\right) by x+5x+5\frac{x+5}{x+5} and the expression with a denominator of (x+4)(x+5)\left(x+4\right)\left(x+5\right) by x+3x+3\frac{x+3}{x+3}.

How To: Given two rational expressions, add or subtract them.

  1. Factor the numerator and denominator.
  2. Find the LCD of the expressions.
  3. Multiply the expressions by a form of 1 that changes the denominators to the LCD.
  4. Add or subtract the numerators.
  5. Simplify.

Example: Adding Rational Expressions

Add the rational expressions:
5x+6y\frac{5}{x}+\frac{6}{y}

Answer: First, we have to find the LCD. In this case, the LCD will be xyxy. We then multiply each expression by the appropriate form of 1 to obtain xyxy as the denominator for each fraction.

5x⋅yy+6y⋅xx5yxy+6xxy\begin{array}{l}\frac{5}{x}\cdot \frac{y}{y}+\frac{6}{y}\cdot \frac{x}{x}\\ \frac{5y}{xy}+\frac{6x}{xy}\end{array}
Now that the expressions have the same denominator, we simply add the numerators to find the sum.
6x+5yxy\frac{6x+5y}{xy}

Analysis of the Solution

Multiplying by yy\frac{y}{y} or xx\frac{x}{x} does not change the value of the original expression because any number divided by itself is 1, and multiplying an expression by 1 gives the original expression.  

Example: Subtracting Rational Expressions

Subtract the rational expressions:
6x2+4x+4−2x2−4\frac{6}{{x}^{2}+4x+4}-\frac{2}{{x}^{2}-4}

Answer:

6(x+2)2−2(x+2)(x−2)Factor.6(x+2)2⋅x−2x−2−2(x+2)(x−2)⋅x+2x+2Multiply each fraction to get LCD as denominator.6(x−2)(x+2)2(x−2)−2(x+2)(x+2)2(x−2)Multiply.6x−12−(2x+4)(x+2)2(x−2)Apply distributive property.4x−16(x+2)2(x−2)Subtract.4(x−4)(x+2)2(x−2)Simplify.\begin{array}{cc}\frac{6}{{\left(x+2\right)}^{2}}-\frac{2}{\left(x+2\right)\left(x - 2\right)}\hfill & \text{Factor}.\hfill \\ \frac{6}{{\left(x+2\right)}^{2}}\cdot \frac{x - 2}{x - 2}-\frac{2}{\left(x+2\right)\left(x - 2\right)}\cdot \frac{x+2}{x+2}\hfill & \text{Multiply each fraction to get LCD as denominator}.\hfill \\ \frac{6\left(x - 2\right)}{{\left(x+2\right)}^{2}\left(x - 2\right)}-\frac{2\left(x+2\right)}{{\left(x+2\right)}^{2}\left(x - 2\right)}\hfill & \text{Multiply}.\hfill \\ \frac{6x - 12-\left(2x+4\right)}{{\left(x+2\right)}^{2}\left(x - 2\right)}\hfill & \text{Apply distributive property}.\hfill \\ \frac{4x - 16}{{\left(x+2\right)}^{2}\left(x - 2\right)}\hfill & \text{Subtract}.\hfill \\ \frac{4\left(x - 4\right)}{{\left(x+2\right)}^{2}\left(x - 2\right)}\hfill & \text{Simplify}.\hfill \end{array}

Q & A

Do we have to use the LCD to add or subtract rational expressions?

No. Any common denominator will work, but it is easiest to use the LCD.

Try It

Subtract the rational expressions: 3x+5−1x−3\frac{3}{x+5}-\frac{1}{x - 3}.

Answer: 2(x−7)(x+5)(x−3)\frac{2\left(x - 7\right)}{\left(x+5\right)\left(x - 3\right)}

Q & A

Can a complex rational expression always be simplified?

Yes. We can always rewrite a complex rational expression as a simplified rational expression.

Key Concepts

  • Rational expressions can be simplified by cancelling common factors in the numerator and denominator.
  • We can multiply rational expressions by multiplying the numerators and multiplying the denominators.
  • To divide rational expressions, multiply by the reciprocal of the second expression.
  • Adding or subtracting rational expressions requires finding a common denominator.
  • Complex rational expressions have fractions in the numerator or the denominator. These expressions can be simplified.

Glossary

least common denominator the smallest multiple that two denominators have in common rational expression the quotient of two polynomial expressions

Licenses & Attributions